Question

harris interactive conducted a survey in which they asked adult americans (18 years or older) whether they used social media (facebook, twitter, and so on) regularly. the following table is a subsample based on the results of the survey. complete parts (a) through (d). click the icon to view the table. (a) if an adult american is randomly selected, what is the probability they use social media? p(use social media) = 0.641 (round to three decimal places as needed.) (b) if an adult american is randomly selected, what is the probability they are 45 to 54 years of age? p(45 - 54) = 0.270 (round to three decimal places as needed.) (c) if an adult american is randomly selected, what is the probability they are a 35 - to 44 - year - old social media user? p(35 - 44 and use social media) = □ (round to three decimal places as needed.) contingency table

Explanation:

Step1: <Find the number of 35 - 44 year - olds who use social media>

From the contingency table, the number of 35 - 44 year - olds who use social media is \(88\).

Step2: <Find the total number of people surveyed>

The total number of people surveyed is \(504\).

Step3: <Calculate the probability>

The probability formula is \(P(A)=\frac{n(A)}{n(S)}\), where \(n(A)\) is the number of elements in event \(A\) and \(n(S)\) is the number of elements in the sample space.
So \(P(35 - 44\text{ and use social media})=\frac{88}{504}\)
\(\frac{88}{504}\approx0.175\)

Answer:

\(0.175\)