Question

a group of data items and their mean are given.
9, 15, 21, 36, 54, 81 ; mean = 36
a. find the deviation from the mean for each of the data items.
b. find the sum of the deviations in part (a).
a. type the deviation from the mean for each of the data items.
9 15 21 36 54 81
(simplify your answers.)

Explanation:

Step1: Calculate deviation for 9

Deviation = Data item - Mean. So, \(9 - 36=- 27\)

Step2: Calculate deviation for 15

\(15 - 36=-21\)

Step3: Calculate deviation for 21

\(21 - 36=-15\)

Step4: Calculate deviation for 36

\(36 - 36 = 0\)

Step5: Calculate deviation for 54

\(54 - 36=18\)

Step6: Calculate deviation for 81

\(81 - 36 = 45\)

Answer:

-9: \(-27\)
-15: \(-21\)
-21: \(-15\)
-36: \(0\)
-54: \(18\)
-81: \(45\)