Question

the graph shows the ages of different concertgoers who have backstage passes. which statement is true about the graph? a late arrival who is 21 years old with a back - stage pass will make the mean greater than the median. the two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age. the ages of concert - goers with backstage passes are skewed left, so the mean age is less than the median age. a concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.

Explanation:

Step1: Understand mean and median concepts

Mean is the average value, median is the middle - value when data is ordered.

Step2: Analyze the skewness of the data

The data is skewed right (longer tail on the right side, as there are a few older ages). In a right - skewed distribution, the mean is pulled in the direction of the tail and is greater than the median. The two ages above 40 are in the tail and will make the mean higher than the median.

Step3: Analyze each option

• Option 1: A 21 - year - old is in the main cluster of data, so it won't make mean > median.
• Option 2: Correct as explained above.
• Option 3: The data is skewed right, not left.
• Option 4: An 18 - year - old is in the main cluster, so it won't pull the mean much relative to the median.

Answer:

The two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age.