Question

gizmo warm - up
just as a cook follows a recipe to decide how much of each
ingredient to add, a chemist uses stoichiometry to determine
the amounts of substances involved in chemical reactions. the
stoichiometry gizmo allows you to try your hand at figuring out
the amounts of reactants and products that take part in a
chemical reaction.
to begin, check that this equation is shown:
\text{fe}_2\text{o}_3 + 3\text{co} \to 2\text{fe} + 3\text{co}_2

1. look at the coefficients (such as the \3\ in 3co) in front of each substance in the equation. the

coefficients tell you how many molecules or atoms take part in a chemical reaction. in the spaces below, list
the number of each molecule or atom in the equation:
\text{fe}_2\text{o}_3 quad \text{co} quad \text{fe} quad \text{co}_2

1. in a balanced equation, the same number of each kind of atom is shown on each side of the equation.

calculate the number of iron (fe), oxygen (o), and carbon atoms (c).
reactants iron:
oxygen:
carbon:
products iron:
oxygen:
carbon:
based on these values, is the equation balanced?

Explanation:

Step1: Count coefficients

The coefficients are the numbers in front of each substance. For \(Fe_2O_3\), the coefficient is \(1\) (implied if not written). For \(CO\), it's \(3\). For \(Fe\), it's \(2\). For \(CO_2\), it's \(3\).

Step2: Calculate atoms in reactants

• Iron (\(Fe\)): In \(Fe_2O_3\), there are \(2\) atoms (from \(Fe_2\)).
• Oxygen (\(O\)): In \(Fe_2O_3\), there are \(3\) atoms (from \(O_3\)); in \(3CO\), there are \(3\times1 = 3\) atoms. Total \(3 + 3=6\) atoms.
• Carbon (\(C\)): In \(3CO\), there are \(3\times1 = 3\) atoms.

Step3: Calculate atoms in products

• Iron (\(Fe\)): In \(2Fe\), there are \(2\) atoms.
• Oxygen (\(O\)): In \(3CO_2\), there are \(3\times2 = 6\) atoms.
• Carbon (\(C\)): In \(3CO_2\), there are \(3\times1 = 3\) atoms.

Answer:

1. \(Fe_2O_3\): \(1\); \(CO\): \(3\); \(Fe\): \(2\); \(CO_2\): \(3\)
2. Reactants - Iron: \(2\); Oxygen: \(6\); Carbon: \(3\)

Products - Iron: \(2\); Oxygen: \(6\); Carbon: \(3\)
The equation is balanced.