Question

1. gerald is riding his bicycle directly east. his maximum instantaneous velocity was 8 meters per second and his minimum instantaneous velocity was 0 meters per second. he covered 7.20 kilometers in 30.0 minutes. what is his average velocity for the trip? 0 m/s east 6 m/s east 8 m/s east 4 m/s east

Explanation:

Step1: Convert units

Convert distance \(d = 7.20\space km\) to meters: \(d=7.20\times1000 = 7200\space m\). Convert time \(t = 30.0\space min\) to seconds: \(t = 30.0\times60=1800\space s\).

Step2: Use average velocity formula

The formula for average velocity \(v_{avg}=\frac{\Delta x}{\Delta t}\). Substitute \(d\) (displacement, since he moves in a straight line east) and \(t\) into the formula: \(v_{avg}=\frac{7200\space m}{1800\space s}\).

Answer:

\(4\space m/s\space east\) (the fourth option)