Question

1. georgia recorded her test results in first term below:

75, 68, 73, 95, 76, 70

a) what is her mean score?

b) what is her median score?

c) which mark is the outlier?

d) calculate the mean without the outlier.

e) calculate the median without the outlier.

Explanation:

Part (a)

Step1: Sum the scores

Sum = \( 75 + 68 + 73 + 95 + 76 + 70 \) = \( 75+68=143 \); \( 143+73=216 \); \( 216+95=311 \); \( 311+76=387 \); \( 387+70=457 \)

Step2: Divide by number of scores (6)

Mean = \( \frac{457}{6} \approx 76.17 \)

Step1: Order the scores

Ordered scores: \( 68, 70, 73, 75, 76, 95 \)

Step2: Find median (average of 3rd and 4th)

Median = \( \frac{73 + 75}{2} = \frac{148}{2} = 74 \)

Step1: Identify outlier

An outlier is a value far from others. Here, 95 is much higher than 68, 70, 73, 75, 76.

Answer:

Approximately \( 76.17 \)

Part (b)