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in a genetics experiment on peas, one sample of offspring contained 363…

Question

in a genetics experiment on peas, one sample of offspring contained 363 green peas and 286 yellow peas. based on those results, estimate the probability is green. is the result reasonably close to the value of $\frac{3}{4}$ that was expected?
the probability of getting a green pea is approximately
(type an integer or decimal rounded to three decimal places as needed.)

Explanation:

Step1: Calculate the total number of peas

The total number of peas is the sum of green peas and yellow peas.
$$363 + 286=649$$

Step2: Calculate the probability of getting a green pea

The probability \(P\) of an event is given by the formula \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, the number of favorable outcomes (green peas) is \(363\), and the total number of outcomes is \(649\).
$$P=\frac{363}{649}\approx0.560863$$
Rounding to three decimal places, \(P\approx0.561\)

Answer:

The probability of getting a green pea is approximately \(0.561\). Since \(0.561\) is not close to \(\frac{3}{4} = 0.75\), the result is not reasonably close to the expected value.