Question

a gas with an unknown volume is originally 588 k. when the volume of the gas changes to 852 ml, the temperature changes to 725 k. what is the initial volume of the gas? v = ? ml assume that the number of moles and the pressure remain constant. volume (ml)

Explanation:

Step1: Apply Charles's Law

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$
where $V_1$=initial volume, $T_1=588\ \text{K}$, $V_2=852\ \text{mL}$, $T_2=725\ \text{K}$

Step2: Rearrange for $V_1$

$V_1 = V_2 \times \frac{T_1}{T_2}$

Step3: Calculate $V_1$

$V_1 = 852 \times \frac{588}{725} \approx 689$

Answer:

689 mL