Question

a gas mixture contains 0.150 mol of oxygen (o₂) gas and 0.211 mol of argon (ar) gas. what is the mole fraction of o₂ in the mixture?
select the correct answer below:
0.416
0.711
1.41
0.0610

Explanation:

Step1: Calculate total moles

Total moles \(n_{total}=n_{O_2}+n_{Ar}\)
\(n_{total}=0.150 + 0.211=0.361\space mol\)

Step2: Calculate mole fraction of \(O_2\)

Mole fraction formula \(X_{O_2}=\frac{n_{O_2}}{n_{total}}\)
\(X_{O_2}=\frac{0.150}{0.361}\approx0.416\)

Answer:

A. 0.416