Question

the gas in a 250.0 ml piston experiences a change in pressure from 1.25 atm to 2.50 atm.
what is the new volume (in ml), assuming the moles of gas and temperature are held constant?
answer:

ml

Explanation:

Step1: Identify the formula

Boyle's Law: \(P_1V_1 = P_2V_2\) (where \(P\) is pressure and \(V\) is volume)

Step2: Rearrange the formula to solve for \(V_2\)

\(V_2=\frac{P_1V_1}{P_2}\)

Step3: Substitute the given values

\(P_1 = 1.25\) atm, \(V_1=250.0\) mL, \(P_2 = 2.50\) atm
\(V_2=\frac{1.25\times250.0}{2.50}\)

Step4: Calculate the value

\(V_2=\frac{312.5}{2.50}=125\)

Answer:

\(125\)