Question

3
frankie ate \\(\frac{3}{8}\\) of a granola bar. her friend pablo ate \\(\frac{4}{8}\\) of the same granola bar.
a what fraction of the granola bar did they eat in all?
b how much of the granola bar is left?
4 write each fraction as an equivalent fraction with 100 in the denominator.
\\(\frac{4}{10} = \frac{40}{100}\\)
\\(\frac{2}{10} = \frac{\quad}{100}\\)
\\(\frac{6}{10} = \frac{\quad}{100}\\)
\\(\frac{9}{10} = \frac{\quad}{100}\\)
\\(\frac{5}{10} = \frac{\quad}{100}\\)
5 add or subtract.
a \\(1\frac{3}{4} + 3\frac{2}{4} = \frac{\quad}{\quad}\\)
b \\(\frac{50}{100} - \frac{2}{10} = \frac{\quad}{\quad}\\)
c \\(\frac{10}{12} - \frac{\quad}{\quad} = \frac{4}{12}\\)

Explanation:

Step1: Solve Problem 3a

To find the total fraction eaten, add the fractions Frankie and Pablo ate. Frankie ate $\frac{3}{8}$ and Pablo ate $\frac{4}{8}$. So, $\frac{3}{8} + \frac{4}{8} = \frac{3 + 4}{8} = \frac{7}{8}$.

Step2: Solve Problem 3b

The whole granola bar is represented by 1 (or $\frac{8}{8}$). Subtract the total fraction eaten ($\frac{7}{8}$) from 1. So, $1 - \frac{7}{8} = \frac{8}{8} - \frac{7}{8} = \frac{1}{8}$.

Step3: Solve Problem 4 (Find equivalent fractions with denominator 100)

• For $\frac{2}{10}$: Multiply numerator and denominator by 10. $\frac{2 \times 10}{10 \times 10} = \frac{20}{100}$.
• For $\frac{6}{10}$: Multiply numerator and denominator by 10. $\frac{6 \times 10}{10 \times 10} = \frac{60}{100}$.
• For $\frac{9}{10}$: Multiply numerator and denominator by 10. $\frac{9 \times 10}{10 \times 10} = \frac{90}{100}$.
• For $\frac{5}{10}$: Multiply numerator and denominator by 10. $\frac{5 \times 10}{10 \times 10} = \frac{50}{100}$.

Step4: Solve Problem 5a

Add the mixed numbers $1\frac{3}{4}$ and $3\frac{2}{4}$. Add the whole numbers: $1 + 3 = 4$. Add the fractions: $\frac{3}{4} + \frac{2}{4} = \frac{5}{4} = 1\frac{1}{4}$. Then add the results: $4 + 1\frac{1}{4} = 5\frac{1}{4}$ (or $\frac{21}{4}$). Wait, the original handwritten answer was 40/10? Wait, maybe a miscalculation. Wait, $1\frac{3}{4} = \frac{7}{4}$, $3\frac{2}{4} = \frac{14}{4}$. Then $\frac{7}{4} + \frac{14}{4} = \frac{21}{4} = 5\frac{1}{4}$. Maybe the handwritten answer was incorrect. But following the problem, let's do it properly.

Step5: Solve Problem 5b

Subtract $\frac{2}{10}$ from $\frac{50}{100}$. First, convert $\frac{2}{10}$ to $\frac{20}{100}$. Then $\frac{50}{100} - \frac{20}{100} = \frac{30}{100} = \frac{3}{10}$. The handwritten answer was 2/10, which is incorrect. Correct answer is $\frac{3}{10}$ (or $\frac{30}{100}$).

Step6: Solve Problem 5c

We know $\frac{10}{12} - x = \frac{4}{12}$. So, $x = \frac{10}{12} - \frac{4}{12} = \frac{6}{12} = \frac{1}{2}$.

Answer:

• 3a: $\frac{7}{8}$
• 3b: $\frac{1}{8}$
• 4: $\frac{2}{10} = \frac{20}{100}$, $\frac{6}{10} = \frac{60}{100}$, $\frac{9}{10} = \frac{90}{100}$, $\frac{5}{10} = \frac{50}{100}$
• 5a: $\frac{21}{4}$ (or $5\frac{1}{4}$)
• 5b: $\frac{3}{10}$ (or $\frac{30}{100}$)
• 5c: $\frac{1}{2}$ (or $\frac{6}{12}$)