Question

the following pictograph shows the approximate attendance at four big sky high school winter sporting events. estimate how many attended each attendance at big sky high school sporting events each \\( \bigcirc \\) represents 1000 people \\( \square \\) people attended boys soccer. \\( \square \\) people attended girls soccer. \\( \square \\) people attended boys basketball. \\( \square \\) people attended girls basketball.

Explanation:

Step1: Analyze Boy's Soccer

Count full circles and partial circles. Boy's soccer has 4 full circles. Each circle is 1000 people, so \(4\times1000 = 4000\) people.

Step2: Analyze Girl's Soccer

Girl's soccer has 4 full circles and a partial circle (let's say ~0.5). So total is \(4\times1000 + 500= 4500\) (approx, but maybe the partial is different, but let's check each):
Wait, re - examining:

• Boy's Soccer: 4 full circles. So \(4\times1000 = 4000\)
• Girl's Soccer: 4 full circles and a half - like? Wait, the pictograph: Boy's soccer: 4 circles. Girl's soccer: 4 circles and a half? Wait, no, let's look again.

Wait, the problem is to estimate for each:

1. Boy's Soccer: 4 full circles. Each = 1000, so \(4\times1000 = 4000\)
2. Girl's Soccer: 4 full circles and a quarter? Wait, no, the image: Girl's soccer has 4 full and a partial (maybe 0.25? But maybe the intended is:

Wait, let's do each:

• Boy's Soccer: 4 circles. So \(4\times1000 = 4000\)
• Girl's Soccer: 4 circles + 0.5 (assuming the partial is half) → \(4.5\times1000 = 4500\)
• Boy's Basketball: 3 full circles and a small partial (maybe 0.1? No, the image: Boy's basketball has 3 full and a tiny part. Wait, no, looking at the columns:

Boy's Basketball: 3 full circles and a small segment. Let's say 3.1×1000≈3100? No, maybe the problem is to count the number of circles (full and partial as fractions).
Wait, the key is each circle is 1000. So:

• Boy's Soccer: 4 circles → \(4\times1000 = 4000\)
• Girl's Soccer: 4 circles + 0.5 (the partial looks like half a circle) → \(4.5\times1000 = 4500\)
• Boy's Basketball: 3 circles + 0.1 (the small part) → ~3100? No, maybe the partial is 0.25. Wait, maybe the problem is simpler: count the number of full circles and approximate partials.

But let's do each:

1. People attended boy’s soccer: 4 circles → \(4\times1000 = 4000\)
2. People attended girl’s soccer: 4 circles + 0.5 (half - circle) → \(4.5\times1000 = 4500\)
3. People attended boy’s basketball: 3 circles + 0.1 (small part) → ~3100? Wait, no, the boy's basketball column: 3 full circles and a tiny segment. Maybe 3.1×1000 = 3100, but maybe the intended is 3.1 is 3100, but let's check the girl's basketball:

Girl's Basketball: 2 full circles and a three - quarter circle. So \(2.75\times1000 = 2750\)
But maybe the problem is to just count the number of circles (treating partials as fractions). Let's assume:

• Boy's Soccer: 4 circles → 4000
• Girl's Soccer: 4.5 circles → 4500
• Boy's Basketball: 3.1 circles → 3100 (approx)
• Girl's Basketball: 2.75 circles → 2750 (approx)

But since the problem is to estimate, we can calculate each:

Step1: Boy's Soccer

Number of circles: 4 (full). Each circle = 1000. So \(4\times1000 = 4000\)

Step2: Girl's Soccer

Number of circles: 4 full + 0.5 (partial). So \(4.5\times1000 = 4500\)

Step3: Boy's Basketball

Number of circles: 3 full + 0.1 (partial, small). So \(3.1\times1000 = 3100\) (approx)

Step4: Girl's Basketball

Number of circles: 2 full + 0.75 (partial, three - quarter). So \(2.75\times1000 = 2750\) (approx)

Answer:

• People attended boy’s soccer: \(\boldsymbol{4000}\)
• People attended girl’s soccer: \(\boldsymbol{4500}\)
• People attended boy’s basketball: \(\boldsymbol{3100}\) (approx, depending on partial)
• People attended girl’s basketball: \(\boldsymbol{2750}\) (approx, depending on partial)

(Note: The exact values depend on the interpretation of the partial circles. If the partial circles are considered as follows: Girl's basketball has 2 full and a three - quarter, Boy's basketball has 3 full and a tenth, etc. But the key is using the 1000 per circle and counting the number of circle - equivalents.)