Question

does this follow
2feso4→fe2o3+so2+so3
model:

atoms:

mass: 14g
does this follow the law of conservation of mass?

Explanation:

Step1: Count atoms of each element in reactants

• For Fe: In \(2FeSO_4\), the number of Fe atoms is \(2\) (since coefficient is \(2\) and sub - script of Fe is \(1\) in \(FeSO_4\)).
• For S: In \(2FeSO_4\), the number of S atoms is \(2\) (coefficient \(2\) and sub - script of S is \(1\) in \(FeSO_4\)).
• For O: In \(2FeSO_4\), the number of O atoms is \(2\times4 = 8\) (coefficient \(2\) and sub - script of O is \(4\) in \(FeSO_4\)).

Step2: Count atoms of each element in products

• For Fe: In \(Fe_2O_3\), the number of Fe atoms is \(2\).
• For S: In \(SO_2+SO_3\), the number of S atoms is \(1 + 1=2\).
• For O: In \(Fe_2O_3+SO_2+SO_3\), the number of O atoms is \(3+2 + 3=8\).

Step3: Check mass conservation

According to the law of conservation of mass, in a chemical reaction, the mass of reactants is equal to the mass of products. Here, since the number of atoms of each element (Fe, S, O) is the same on both sides of the reaction \(2FeSO_4
ightarrow Fe_2O_3+SO_2+SO_3\), if we assume the reaction goes to completion and there is no loss (in a closed system), the mass of reactants (mass of \(2FeSO_4\)) is equal to the mass of products (mass of \(Fe_2O_3+SO_2+SO_3\)).

Answer:

Element	# in Reactants	# in Products
S	2	2
O	8	8

Mass: \(14g\) (mass of reactants) \(
ightarrow14g\) (mass of products)
Does this follow the LAW of Conservation of Mass? Yes.