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five hawksbill sea turtles each have a nest. the table shows an origina…

Question

five hawksbill sea turtles each have a nest. the table shows an original data set of the number of eggs that each turtle laid in its nest. a sixth nest with 121 eggs is added to create a new data set. which of the following correctly compares the means of the two data sets? the mean of the original data set is greater than the mean of the new data set. the mean of the original data set is less than the mean of the new data

Explanation:

Step1: Sum original data

Sum = 148 + 141 + 146 + 136 + 139 = 710

Step2: Mean of original data

Mean = $\frac{710}{5}$ = 142

Step3: Sum new data

New sum = 710 + 121 = 831

Step4: Mean of new data

New mean = $\frac{831}{6}$ = 138.5

Step5: Compare means

142 > 138.5, so original mean > new mean.

Answer:

A. The mean of the original data set is greater than the mean of the new data set.