Question

finding the equation of a trend line
height and forearm
fred needs to write the equation of the line. he used (10, 64) and (12.5, 73) to find the slope, which is 3.6.
the equation of the trend line is

Explanation:

Step1: Use point - slope form

The point - slope form of a line is \(y - y_1=m(x - x_1)\), where \(m\) is the slope and \((x_1,y_1)\) is a point on the line. We know \(m = 3.6\). Let's use the point \((10,64)\) (we could also use \((12.5,73)\)).
Substitute \(m = 3.6\), \(x_1=10\), and \(y_1 = 64\) into the point - slope formula: \(y-64=3.6(x - 10)\).

Step2: Simplify the equation

First, distribute the \(3.6\) on the right side: \(y-64=3.6x-36\).
Then, add \(64\) to both sides of the equation. Using the addition property of equality \(y=3.6x-36 + 64\).
Simplify the right side: \(y=3.6x + 28\).

Answer:

\(y = 3.6x+28\)