Question

find the probability ( p(e \text{ or } f) ) if ( e ) and ( f ) are mutually exclusive, ( p(e)=0.25 ), and ( p(f)=0.47 ).
the probability ( p(e \text{ or } f) ) is (simplify your answer.)

Explanation:

Step1: Recall the formula for mutually exclusive events

For mutually exclusive events \(E\) and \(F\), \(P(E\ or\ F)=P(E)+P(F)\).

Step2: Substitute the given values

Given \(P(E) = 0.25\) and \(P(F)=0.47\), then \(P(E\ or\ F)=0.25 + 0.47\).

Step3: Calculate the sum

\(0.25+0.47 = 0.72\).

Answer:

\(0.72\)