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find the probability of exactly two successes in five trials of a binom…

Question

find the probability of exactly two successes in five trials of a binomial experiment in which the probability of success is 50%. p = ?%

Explanation:

Step1: Recall the binomial probability formula

The binomial probability formula is \(P(X = k)=C(n,k)\times p^{k}\times(1 - p)^{n - k}\), where \(n\) is the number of trials, \(k\) is the number of successes, \(p\) is the probability of success in a single trial, and \(C(n,k)=\frac{n!}{k!(n - k)!}\)

Step2: Identify the values of \(n\), \(k\), and \(p\)

Here, \(n = 5\), \(k=2\), \(p = 0.5\) (since \(50\%=0.5\)), and \(1-p=0.5\)

Step3: Calculate the combination \(C(n,k)\)

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Step4: Substitute the values into the binomial probability formula

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Step5: Convert the probability to a percentage

Multiply the probability by \(100\) to get the percentage. \(0.3125\times100 = 31.25\%\)

Answer:

\(31.25\%\)