Question

find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p.

(n = 90), (p = 0.9)

the mean, (mu), is 81. (round to the nearest tenth as needed.)

the variance, (sigma^2), is . (round to the nearest tenth as needed.)

Explanation:

Calculate the mean

$$ \mu = n \cdot p = 90 \cdot 0.9 = 81 $$

Calculate the variance

$$
LATEXBLOCK0
$$

Answer:

Question 1

The mean, \(\mu\), is <blank>81</blank>. (Round to the nearest tenth as needed.)

Question 2

The variance, \(\sigma^2\), is <blank>8.1</blank>. (Round to the nearest tenth as needed.)