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find p(z > -3.35)

Question

find p(z > -3.35)

Explanation:

Step1: Use the property of the standard normal distribution

We know that \(P(Z > a)=1 - P(Z\leq a)\) for a standard - normal random variable \(Z\). Here \(a=-3.35\), so \(P(Z > - 3.35)=1 - P(Z\leq - 3.35)\)

Step2: Look up the value in the standard - normal table

Looking up the value of \(P(Z\leq - 3.35)\) in the standard - normal table (the cumulative distribution function of the standard normal distribution \(\varPhi(z)\)). The value of \(P(Z\leq - 3.35)\) is approximately \(0.0004\)

Step3: Calculate the probability

Substitute the value of \(P(Z\leq - 3.35)\) into the formula from Step1. \(P(Z > - 3.35)=1-0.0004 = 0.9996\)

Answer:

\(0.9996\)