fill in the table below with the correct model, molecular geometry, and bond angle of the given formula
formula shape/model (image) molecular geometry/name bond angle
h₂o
co₂
so₂
bf₃
nh₃
ch₄

Question

Accepted Answer

# Brief Explanations:
- For $H_2O$:
  - The shape/model is a bent - like structure (V - shaped).
  - Molecular geometry is bent.
  - Bond angle is approximately $104.5^{\circ}$ due to the two lone pairs on the oxygen atom which repel the bonding pairs more strongly than in a tetrahedral - like (without lone pairs) situation.
- For $CO_2$:
  - The shape/model is a linear structure.
  - Molecular geometry is linear.
  - Bond angle is $180^{\circ}$ as the carbon atom has $sp$ hybridization and there are no lone pairs to distort the linear arrangement of the two double bonds.
- For $SO_2$:
  - The shape/model is a bent - like structure.
  - Molecular geometry is bent.
  - Bond angle is approximately $119^{\circ}$. Sulfur has $sp^2$ hybridization and one lone pair which causes a deviation from the ideal $120^{\circ}$ (trigonal planar without lone pair) bond angle.
- For $BF_3$:
  - The shape/model is a trigonal planar structure.
  - Molecular geometry is trigonal planar.
  - Bond angle is $120^{\circ}$ as boron has $sp^2$ hybridization and no lone pairs, so the three fluorine atoms are evenly spaced around the boron atom.
- For $NH_3$:
  - The shape/model is a trigonal pyramidal structure.
  - Molecular geometry is trigonal pyramidal.
  - Bond angle is approximately $107^{\circ}$. Nitrogen has $sp^3$ hybridization and one lone pair. The lone pair - bond pair repulsion is stronger than bond pair - bond pair repulsion, reducing the bond angle from the ideal $109.5^{\circ}$ (tetrahedral).
- For $CH_4$:
  - The shape/model is a tetrahedral structure.
  - Molecular geometry is tetrahedral.
  - Bond angle is $109.5^{\circ}$ as carbon has $sp^3$ hybridization and no lone pairs, so the four hydrogen atoms are symmetrically arranged around the carbon atom.

# Answer:
| Formula | Shape/Model (Image) | Molecular Geometry/Name | Bond Angle |
| ---- | ---- | ---- | ---- |
| $H_2O$ | Bent - like (V - shaped) | Bent | $104.5^{\circ}$ |
| $CO_2$ | Linear | Linear | $180^{\circ}$ |
| $SO_2$ | Bent - like | Bent | $119^{\circ}$ |
| $BF_3$ | Trigonal planar | Trigonal planar | $120^{\circ}$ |
| $NH_3$ | Trigonal pyramidal | Trigonal pyramidal | $107^{\circ}$ |
| $CH_4$ | Tetrahedral | Tetrahedral | $109.5^{\circ}$ |

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QUESTION IMAGE

Question

Explanation:

Answer:

Formula	Shape/Model (Image)	Molecular Geometry/Name	Bond Angle
\(CO_2\)	Linear	Linear	\(180^{\circ}\)
\(SO_2\)	Bent - like	Bent	\(119^{\circ}\)
\(BF_3\)	Trigonal planar	Trigonal planar	\(120^{\circ}\)
\(NH_3\)	Trigonal pyramidal	Trigonal pyramidal	\(107^{\circ}\)
\(CH_4\)	Tetrahedral	Tetrahedral	\(109.5^{\circ}\)