fill out the table below based on the following chemical equation: n₂ + o₂ → n₂o₅ the correct coefficients for the equation is: n₂ + o₂ → n₂o₅ total # before (reactants) total # after (reactants) elements

Question

Accepted Answer

# Explanation:
## Step1: Balance the chemical equation
According to the law of conservation of mass, the number of atoms of each element on both sides of the equation must be equal.
For the equation $aN_2 + bO_2
ightarrow cN_2O_5$, for nitrogen ($N$): $2a = 2c$; for oxygen ($O$): $2b=5c$. Let $c = 2$, then $a = 2$, and $b = 5$. The balanced equation is $2N_2+5O_2
ightarrow 2N_2O_5$.
## Step2: Calculate the number of atoms before reaction
For $N$: In $2N_2$, the number of $N$ atoms is $2\times2 = 4$. In $5O_2$, the number of $O$ atoms is $5\times2=10$.
## Step3: Calculate the number of atoms after reaction
In $2N_2O_5$, the number of $N$ atoms is $2\times2 = 4$, and the number of $O$ atoms is $2\times5 = 10$.

# Answer:
| Elements | Total # Before (reactants) | Total # After (Products) |
|--|--|--|
| $N$ | $4$ | $4$ |
| $O$ | $10$ | $10$ |
The balanced equation is $2N_2 + 5O_2
ightarrow2N_2O_5$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance the chemical equation

Step2: Calculate the number of atoms before reaction

Step3: Calculate the number of atoms after reaction

Answer: