QUESTION IMAGE
Question
fill out the table below based on the following chemical equation:
nh3 + hcl → nh4cl
the correct coefficients for the equation is:
nh3 + hcl → nh4cl
elements
total # before (reactants)
total # after (products)
Step1: Balance the chemical equation
The unbalanced equation is \(NH_3 + HCl
ightarrow NH_4Cl\).
For \(N\): There is 1 \(N\) on the left (\(NH_3\)) and 1 \(N\) on the right (\(NH_4Cl\)).
For \(H\): On the left, in \(NH_3\) there are 3 \(H\) and in \(HCl\) there is 1 \(H\), total \(3 + 1=4\) \(H\). On the right, in \(NH_4Cl\) there are 4 \(H\).
For \(Cl\): On the left, in \(HCl\) there is 1 \(Cl\). On the right, in \(NH_4Cl\) there is 1 \(Cl\).
So the balanced equation is \(1NH_3+1HCl
ightarrow1NH_4Cl\).
Step2: Calculate totals
- Before (reactants):
- \(Cl\): In \(HCl\), coefficient is 1, so 1 \(Cl\) atom.
- \(H\): In \(NH_3\) (3 \(H\)) and \(HCl\) (1 \(H\)), total \(3 + 1=4\) \(H\) atoms.
- \(N\): In \(NH_3\), coefficient is 1, so 1 \(N\) atom.
- After (products):
- \(Cl\): In \(NH_4Cl\), coefficient is 1, so 1 \(Cl\) atom.
- \(H\): In \(NH_4Cl\), 4 \(H\) atoms.
- \(N\): In \(NH_4Cl\), 1 \(N\) atom.
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| \(Cl\) | \(H\) | \(N\) | |
|---|---|---|---|
| Total # After (products) | 1 | 4 | 1 |
Coefficients: \(1NH_3 + 1HCl
ightarrow1NH_4Cl\)