Question

fill in the number of valence electron(s) of the elements that are listed li i b p mg

Explanation:

Step1: Determine valence electrons for Li

Li (Lithium) has an electron configuration of \(1s^{2}2s^{1}\). The outermost shell (n = 2) has 1 electron.

Step2: Determine valence electrons for I

I (Iodine) has an electron configuration of \([Kr]4d^{10}5s^{2}5p^{5}\). The outermost shell (n = 5) has \(2 + 5=7\) electrons.

Step3: Determine valence electrons for B

B (Boron) has an electron configuration of \(1s^{2}2s^{2}2p^{1}\). The outermost shell (n = 2) has \(2 + 1 = 3\) electrons.

Step4: Determine valence electrons for P

P (Phosphorus) has an electron configuration of \([Ne]3s^{2}3p^{3}\). The outermost shell (n = 3) has \(2+3 = 5\) electrons.

Step5: Determine valence electrons for Mg

Mg (Magnesium) has an electron configuration of \(1s^{2}2s^{2}2p^{6}3s^{2}\). The outermost shell (n = 3) has 2 electrons.

Answer:

Li: 1; I: 7; B: 3; P: 5; Mg: 2