Question

fill in the left side of this equilibrium constant equation for the reaction of hydrofluoric acid (hf) with water.
square = k _ { a }

Explanation:

Step1: Write the dissociation reaction of HF

Hydrofluoric acid (\(HF\)) reacts with water (\(H_2O\)) as follows: \(HF(aq)+H_2O(l)
ightleftharpoons H_3O^{+}(aq)+F^{-}(aq)\)

Step2: Recall the formula for \(K_a\)

The acid - dissociation constant \(K_a\) is given by the formula \(K_a=\frac{[H_3O^{+}][F^{-}]}{[HF]}\)

Answer:

\(\frac{[H_3O^{+}][F^{-}]}{[HF]}\)