Question

3 fill in the electrons for the following elements. how many valence electron does each electron have? c: 1s 2 2s 2 2p 3s 3p. number li: 1s 2s 2p 3s 3p. number ar: 1s 2s 2p 3s 3p. number cl: 1s 2s 2p 3s 3p. number

Explanation:

Step1: Recall electron - configuration rules

Electrons fill orbitals in a specific order (1s < 2s < 2p < 3s < 3p etc.) and s - orbitals can hold 2 electrons, p - orbitals can hold 6 electrons. Valence electrons are in the out - most shell.

Step2: Determine electron configuration for Carbon (C)

Carbon has an atomic number of 6. Its electron configuration is 1s$^2$2s$^2$2p$^2$. The out - most shell is the second shell (n = 2), and the number of valence electrons is 4 (2 in 2s and 2 in 2p). So for C: 1s$^2$2s$^2$2p$^2$3s$^0$3p$^0$, number of valence electrons = 4.

Step3: Determine electron configuration for Chlorine (Cl)

Chlorine has an atomic number of 17. Its electron configuration is 1s$^2$2s$^2$2p$^6$3s$^2$3p$^5$. The out - most shell is the third shell (n = 3), and the number of valence electrons is 7 (2 in 3s and 5 in 3p). So for Cl: 1s$^2$2s$^2$2p$^6$3s$^2$3p$^5$, number of valence electrons = 7.

Step4: Determine electron configuration for Lithium (Li)

Lithium has an atomic number of 3. Its electron configuration is 1s$^2$2s$^1$. The out - most shell is the second shell (n = 2), and the number of valence electrons is 1 (in 2s). So for Li: 1s$^2$2s$^1$2p$^0$3s$^0$3p$^0$, number of valence electrons = 1.

Step5: Determine electron configuration for Argon (Ar)

Argon has an atomic number of 18. Its electron configuration is 1s$^2$2s$^2$2p$^6$3s$^2$3p$^6$. The out - most shell is the third shell (n = 3), and the number of valence electrons is 8 (2 in 3s and 6 in 3p). So for Ar: 1s$^2$2s$^2$2p$^6$3s$^2$3p$^6$, number of valence electrons = 8.

Answer:

C: 1s$^2$2s$^2$2p$^2$3s$^0$3p$^0$, 4 valence electrons
Cl: 1s$^2$2s$^2$2p$^6$3s$^2$3p$^5$, 7 valence electrons
Li: 1s$^2$2s$^1$2p$^0$3s$^0$3p$^0$, 1 valence electron
Ar: 1s$^2$2s$^2$2p$^6$3s$^2$3p$^6$, 8 valence electrons