Question

fill in the blank.

if \\(n(e_1 \text{ and } e_2) = 4\\) and \\(n(e_1) = 18\\), then \\(p(e_2|e_1) = \underline{\quad\quad}\\).

if \\(n(e_1 \text{ and } e_2) = 4\\) and \\(n(e_1) = 18\\), then \\(p(e_2|e_1) = \square\\).
(type an integer or a simplified fraction.)

Explanation:

Apply conditional probability formula

Using the Conditional Probability knowledge point

$$ P(E_2 | E_1) = \frac{n(E_1 \text{ and } E_2)}{n(E_1)} $$

Substitute the given values

Using the Conditional Probability knowledge point

$$ P(E_2 | E_1) = \frac{4}{18} $$

Simplify the fraction

Using the Fraction Simplification knowledge point

$$ P(E_2 | E_1) = \frac{2}{9} $$

Answer:

If \(n(E_1 \text{ and } E_2) = 4\) and \(n(E_1) = 18\), then \(P(E_2|E_1) =\) <blank>\(\frac{2}{9}\)</blank>.
(Type an integer or a simplified fraction.)