Question

the figure shows the elements of period 3 and the first 3 elements of group 6a of the periodic table. use the figure to answer questions 10 and 11
which list of symbols, in order from left to right, correctly completes the following passage?
from the group 6a elements shown in the diagram, the element with the largest atomic radius is __. in period 3, the element with the largest atomic radius is . the three atoms which would form ions which are smaller in size than their parent atoms are al, mg, and . in period 3, has the highest ionization energy, while in group 6a __ has the highest ionization energy.
○ se, na, na, ar, o
○ o, ar, na, na, o
○ se, na, cl, ar, se
○ o, ar, cl, na, se

Explanation:

Step1: Atomic radius in Group 6A

Atomic radius increases down a group. In Group 6A (O, S, Se), Se is the lowest - so it has the largest atomic radius.

Step2: Atomic radius in Period 3

Atomic radius decreases across a period. In Period 3 (Na, Mg, Al, Si, P, S, Cl, Ar), Na is on the far left - so it has the largest atomic radius.

Step3: Ions smaller than parent atoms

Metals form cations (lose electrons). Na, Mg, Al are metals. When they lose electrons, their ions are smaller than parent atoms.

Step4: Ionization energy in Period 3

Ionization energy increases across a period (except some minor exceptions). Noble gases (Ar) have full - filled shells, so Ar has the highest ionization energy in Period 3.

Step5: Ionization energy in Group 6A

Ionization energy decreases down a group. O is at the top of Group 6A - so it has the highest ionization energy in Group 6A.

Answer:

Se, Na, Na, Ar, O