Question

ferris wheel roller coaster water slide total
splashland 11 24 18 53
eight pennants 9 19 22 50
cedarwild 27 11 8 46
rainbowrealm 7 27 24 58
warp ventures 10 27 24 61
total 64 108 96 268
event a: choosing warp ventures as a favorite park
p(b) = \frac{96}{268}
probability of choosing war
park and choosing a water s
p(a and b) = \frac{24}{268}
probability of choosing warp ventures as a favorite
park or choosing a water slide as a favorite ride:
p(a or b) = \square

Explanation:

Step1: Recall the formula for \(P(A\ or\ B)\)

The formula for the probability of the union of two events \(A\) and \(B\) is \(P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)\)

Step2: Identify the values of \(P(A)\), \(P(B)\) and \(P(A\ and\ B)\)

From the table, \(n(A) = 61\) (total number of people who chose Warp Ventures), \(n(B)=96\) (total number of people who chose water - slide) and \(n(A\ and\ B) = 24\) (number of people who chose Warp Ventures and water - slide). The total number of people \(n = 268\)
\(P(A)=\frac{61}{268}\), \(P(B)=\frac{96}{268}\) and \(P(A\ and\ B)=\frac{24}{268}\)

Step3: Substitute the values into the formula

$$
LATEXBLOCK0
$$

Answer:

\(\frac{133}{268}\)