Question

1. feo + pdf₂ → fef₂ + pdo

Explanation:

Step1: Count atoms on both sides

On the left - hand side:

• For Fe: 1 atom (from \(FeO\))
• For O: 1 atom (from \(FeO\))
• For Pd: 1 atom (from \(PdF_2\))
• For F: 2 atoms (from \(PdF_2\))

On the right - hand side:

• For Fe: 1 atom (from \(FeF_2\))
• For F: 2 atoms (from \(FeF_2\))
• For Pd: 1 atom (from \(PdO\))
• For O: 1 atom (from \(PdO\))

Step2: Balance the equation

Since the number of each type of atom (\(Fe\), \(O\), \(Pd\), \(F\)) is already the same on both sides of the equation \(FeO+PdF_2
ightarrow FeF_2 + PdO\), the coefficients are \(1\) for each compound.

Answer:

\(1\ FeO+1\ PdF_2
ightarrow1\ FeF_2 + 1\ PdO\)