QUESTION IMAGE
Question
factor the following quadratic expressions.
section a
- \\(x^2 + 7x - 30\\)
- \\(x^2 + 9x + 20\\)
- \\(x^2 + 8x - 9\\)
- \\(x^2 - 18x + 80\\)
- \\(x^2 - 11x + 28\\)
- \\(x^2 + 6x - 72\\)
- \\(x^2 - 9x - 22\\)
- \\(x^2 - x - 12\\)
- \\(x^2 + 3x - 108\\)
- \\(x^2 - 17x + 72\\)
- \\(x^2 - x - 42\\)
- \\(x^2 - 15x + 56\\)
section b
- \\(2x^2 + 3x + 1\\)
- \\(2x^2 + 5x + 2\\)
- \\(2x^2 + 7x + 3\\)
- \\(2x^2 + 7x + 5\\)
- \\(2x^2 + 9x + 7\\)
- \\(2x^2 + 5x + 3\\)
- \\(2x^2 + 8x + 6\\)
- \\(2x^2 + 9x + 10\\)
- \\(2x^2 + 16x + 14\\)
- \\(2x^2 + 18x + 24\\)
- \\(2x^2 + 12x + 18\\)
- \\(2x^2 + 14x + 20\\)
- \\(2x^2 + 22x + 36\\)
- \\(2x^2 + 28x + 48\\)
- \\(2x^2 + 26x + 72\\)
section c
- \\(2x^2 + x - 1\\)
- \\(2x^2 + x - 3\\)
- \\(2x^2 + 9x - 5\\)
- \\(2x^2 - 3x - 2\\)
- \\(2x^2 - 13x - 24\\)
- \\(3x^2 - 14x - 5\\)
- \\(3x^2 - 8x - 11\\)
- \\(2x^2 - 14x + 12\\)
- \\(3x^2 - 21x + 36\\)
- \\(5x^2 - 41x - 8\\)
- \\(3x^2 - 2x - 21\\)
- \\(2x^2 + 2x - 12\\)
- \\(2x^2 - 11x + 15\\)
- \\(3x^2 - 34x - 24\\)
- \\(5x^2 - 27x + 10\\)
section d
- \\(4x^2 + 12x + 8\\)
- \\(6x^2 + 23x + 20\\)
- \\(6x^2 + 24x + 18\\)
- \\(4x^2 + 31x + 21\\)
- \\(4x^2 + 22x + 18\\)
- \\(8x^2 + 22x + 15\\)
- \\(8x^2 + 36x + 16\\)
- \\(6x^2 - 5x - 4\\)
- \\(6x^2 - 16x + 15\\)
- \\(8x^2 + 16x - 24\\)
- \\(7x^2 + 52x - 32\\)
- \\(6x^2 - 55x + 56\\)
- \\(9x^2 + 36x + 35\\)
- \\(12x^2 - 42x + 30\\)
- \\(48x^2 + 72x + 24\\)
- \\(18x^2 + 51x + 8\\)
- \\(20x^2 + 27x + 9\\)
- \\(30x^2 - 32x + 8\\)
- \\(36x^2 + 42x - 8\\)
- \\(24x^2 - 50x - 14\\)
- \\(-2x^2 + x + 21\\)
<pre_analysis>
{
"quality": "clear",
"question_count": 63,
"skills_matched": [
"step_cot",
"explain_then_answer",
"quick"
],
"needs_drawing": false,
"concepts_used": [],
"new_concepts": [
"Quadratic Factoring",
"Cross Multiplication"
],
"current_concepts": [
"Quadratic Factoring",
"Cross Multiplication"
]
}
</pre_analysis>
<reasoning>
由於題目包含大量二次三項式因式分解,我們將依據各個 Section(A, B, C, D)進行系統化的因式分解計算。
Section A:首項係數為 1 的二次式因式分解
尋找兩個數,其積等於常數項,且其和等於一次項係數:
- \(x^2 + 7x - 30 = (x + 10)(x - 3)\)
- \(x^2 + 9x + 20 = (x + 4)(x + 5)\)
- \(x^2 + 8x - 9 = (x + 9)(x - 1)\)
- \(x^2 - 18x + 80 = (x - 8)(x - 10)\)
- \(x^2 - 11x + 28 = (x - 4)(x - 7)\)
- \(x^2 + 6x - 72 = (x + 12)(x - 6)\)
- \(x^2 - 9x - 22 = (x - 11)(x + 2)\)
- \(x^2 - x - 12 = (x - 4)(x + 3)\)
- \(x^2 + 3x - 108 = (x + 12)(x - 9)\)
- \(x^2 - 17x + 72 = (x - 8)(x - 9)\)
- \(x^2 - x - 42 = (x - 7)(x + 6)\)
- \(x^2 - 15x + 56 = (x - 7)(x - 8)\)
Section B:首項係數為 2 且常數項為正的二次式因式分解
利用十字相乘法或提取公因式:
- \(2x^2 + 3x + 1 = (2x + 1)(x + 1)\)
- \(2x^2 + 5x + 2 = (2x + 1)(x + 2)\)
- \(2x^2 + 7x + 3 = (2x + 1)(x + 3)\)
- \(2x^2 + 7x + 5 = (2x + 5)(x + 1)\)
- \(2x^2 + 9x + 7 = (2x + 7)(x + 1)\)
- \(2x^2 + 5x + 3 = (2x + 3)(x + 1)\)
- \(2x^2 + 8x + 6 = 2(x^2 + 4x + 3) = 2(x + 1)(x + 3)\)
- \(2x^2 + 9x + 10 = (2x + 5)(x + 2)\)
- \(2x^2 + 16x + 14 = 2(x^2 + 8x + 7) = 2(x + 1)(x + 7)\)
- \(2x^2 + 10x + 24\)(原圖為 \(2x^2 + 10x + 24\),此式在實數範圍內無法分解為有理係數因式,若為 \(2x^2 + 10x + 12\) 則為 \(2(x+2)(x+3)\);若為 \(2x^2 - 10x + 12\) 則為 \(2(x-2)(x-3)\)。依原圖字樣 \(2x^2 + 10x + 24 = 2(x^2 + 5x + 12)\))
- \(2x^2 + 12x + 18 = 2(x^2 + 6x + 9) = 2(x + 3)^2\)
- \(2x^2 + 14x + 20 = 2(x^2 + 7x + 10) = 2(x + 2)(x + 5)\)
- \(2x^2 + 22x + 36 = 2(x^2 + 11x + 18) = 2(x + 2)(x + 9)\)
- \(2x^2 + 28x + 48 = 2(x^2 + 14x + 24) = 2(x + 2)(x + 12)\)
- \(2x^2 + 26x + 72 = 2(x^2 + 13x + 36) = 2(x + 4)(x + 9)\)
Section C:首項係數不為 1 且常數項可正可負的二次式因式分解
- \(2x^2 + x - 1 = (2x - 1)(x + 1)\)
- \(2x^2 + x - 3 = (2x + 3)(x - 1)\)
- \(2x^2 + 9x - 5 = (2x - 1)(x + 5)\)
- \(2x^2 - 3x - 2 = (2x + 1)(x - 2)\)
- \(2x^2 - 13x - 24 = (2x + 3)(x - 8)\)
- \(3x^2 - 14x - 5 = (3x + 1)(x - 5)\)
- \(3x^2 - 8x - 11 = (3x - 11)(x + 1)\)
- \(2x^2 - 14x + 12 = 2(x^2 - 7x + 6) = 2(x - 1)(x - 6)\)
- \(3x^2 - 21x + 36 = 3(x^2 - 7x + 12) = 3(x - 3)(x - 4)\)
- \(5x^2 - 41x - 8 = (5x + 1)(x - 8)\)
- \(3x^2 - 2x - 21 = (3x + 7)(x - 3)\)
- \(2x^2 + 2x - 12 = 2(x^2 + x - 6) = 2(x + 3)(x - 2)\)
- \(2x^2 - 11x + 15 = (2x - 5)(x - 3)\)
- \(3x^2 - 34x - 24 = (3x + 2)(x - 12)\)
- \(5x^2 - 27x + 10 = (5x - 2)(x - 5)\)
Section D:更複雜首項係數的二次式因式分解與挑戰題
- \(4x^2 + 12x + 8 = 4(x^2 + 3x + 2) = 4(x + 1)(x + 2)\)
- \(6x^2 + 23x + 20 = (2x + 5)(3x + 4)\)
- \(6x^2 + 24x + 18 = 6(x^2 + 4x + 3) = 6(x + 1)(x + 3)\)
- \(4x^2 + 31x + 21 = (4x + 3)(x + 7)\)
- \(4x^2 + 22x + 18 = 2(2x^2 + 11x + 9) = 2(2x + 9)(x + 1)\)
- \(8x^2 - 22x + 15 = (2x - 3)(4x - 5)\)
- \(8x^2 + 36x + 16 = 4(2x^2 + 9x + 4) = 4(2x + 1)(x + 4)\)
- \(6x^2 - 5x - 4 = (2x + 1)(3x - 4)\)
- \(6x^2 - 16x + 10\)(原圖為 \(6x^2 - 16x + 15\),此式在實數範圍內無法分解。若為 \(6x^2 - 16x + 10\),則為 \(2(3x - 5)(x - 1)\))
- \(8x^2 + 16x - 24 = 8(x^2 + 2x - 3) = 8(x + 3)(x - 1)\)
- \(7x^2 + 52x - 32 = (7x - 4)(x + 8)\)
- \(6x^2 - 55x + 56 = (6x - 7)(x - 8)\)
- \(9x^2 + 36x + 35 = (3x + 5)(3x + 7)\)
- \(12x^2 - 42x + 30 = 6(2x^2 - 7x + 5) = 6(2x - 5)(x - 1)\)
- \(48x^2 + 72x + 24 = 24(2x^2 + 3x + 1) = 24(2x + 1)(x + 1)\)
- \(18x^2 + 51x + 8\)(原圖為 \(18x^2 + 51x + 8\),此式無法分解。若為 \(18x^2 + 51x + 8\) 則保持原樣;若為 \(18x^2 + 51x + 30 = 3(6x^2 + 17x + 1…
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<pre_analysis>
{
"quality": "clear",
"question_count": 63,
"skills_matched": [
"step_cot",
"explain_then_answer",
"quick"
],
"needs_drawing": false,
"concepts_used": [],
"new_concepts": [
"Quadratic Factoring",
"Cross Multiplication"
],
"current_concepts": [
"Quadratic Factoring",
"Cross Multiplication"
]
}
</pre_analysis>
<reasoning>
由於題目包含大量二次三項式因式分解,我們將依據各個 Section(A, B, C, D)進行系統化的因式分解計算。
Section A:首項係數為 1 的二次式因式分解
尋找兩個數,其積等於常數項,且其和等於一次項係數:
- \(x^2 + 7x - 30 = (x + 10)(x - 3)\)
- \(x^2 + 9x + 20 = (x + 4)(x + 5)\)
- \(x^2 + 8x - 9 = (x + 9)(x - 1)\)
- \(x^2 - 18x + 80 = (x - 8)(x - 10)\)
- \(x^2 - 11x + 28 = (x - 4)(x - 7)\)
- \(x^2 + 6x - 72 = (x + 12)(x - 6)\)
- \(x^2 - 9x - 22 = (x - 11)(x + 2)\)
- \(x^2 - x - 12 = (x - 4)(x + 3)\)
- \(x^2 + 3x - 108 = (x + 12)(x - 9)\)
- \(x^2 - 17x + 72 = (x - 8)(x - 9)\)
- \(x^2 - x - 42 = (x - 7)(x + 6)\)
- \(x^2 - 15x + 56 = (x - 7)(x - 8)\)
Section B:首項係數為 2 且常數項為正的二次式因式分解
利用十字相乘法或提取公因式:
- \(2x^2 + 3x + 1 = (2x + 1)(x + 1)\)
- \(2x^2 + 5x + 2 = (2x + 1)(x + 2)\)
- \(2x^2 + 7x + 3 = (2x + 1)(x + 3)\)
- \(2x^2 + 7x + 5 = (2x + 5)(x + 1)\)
- \(2x^2 + 9x + 7 = (2x + 7)(x + 1)\)
- \(2x^2 + 5x + 3 = (2x + 3)(x + 1)\)
- \(2x^2 + 8x + 6 = 2(x^2 + 4x + 3) = 2(x + 1)(x + 3)\)
- \(2x^2 + 9x + 10 = (2x + 5)(x + 2)\)
- \(2x^2 + 16x + 14 = 2(x^2 + 8x + 7) = 2(x + 1)(x + 7)\)
- \(2x^2 + 10x + 24\)(原圖為 \(2x^2 + 10x + 24\),此式在實數範圍內無法分解為有理係數因式,若為 \(2x^2 + 10x + 12\) 則為 \(2(x+2)(x+3)\);若為 \(2x^2 - 10x + 12\) 則為 \(2(x-2)(x-3)\)。依原圖字樣 \(2x^2 + 10x + 24 = 2(x^2 + 5x + 12)\))
- \(2x^2 + 12x + 18 = 2(x^2 + 6x + 9) = 2(x + 3)^2\)
- \(2x^2 + 14x + 20 = 2(x^2 + 7x + 10) = 2(x + 2)(x + 5)\)
- \(2x^2 + 22x + 36 = 2(x^2 + 11x + 18) = 2(x + 2)(x + 9)\)
- \(2x^2 + 28x + 48 = 2(x^2 + 14x + 24) = 2(x + 2)(x + 12)\)
- \(2x^2 + 26x + 72 = 2(x^2 + 13x + 36) = 2(x + 4)(x + 9)\)
Section C:首項係數不為 1 且常數項可正可負的二次式因式分解
- \(2x^2 + x - 1 = (2x - 1)(x + 1)\)
- \(2x^2 + x - 3 = (2x + 3)(x - 1)\)
- \(2x^2 + 9x - 5 = (2x - 1)(x + 5)\)
- \(2x^2 - 3x - 2 = (2x + 1)(x - 2)\)
- \(2x^2 - 13x - 24 = (2x + 3)(x - 8)\)
- \(3x^2 - 14x - 5 = (3x + 1)(x - 5)\)
- \(3x^2 - 8x - 11 = (3x - 11)(x + 1)\)
- \(2x^2 - 14x + 12 = 2(x^2 - 7x + 6) = 2(x - 1)(x - 6)\)
- \(3x^2 - 21x + 36 = 3(x^2 - 7x + 12) = 3(x - 3)(x - 4)\)
- \(5x^2 - 41x - 8 = (5x + 1)(x - 8)\)
- \(3x^2 - 2x - 21 = (3x + 7)(x - 3)\)
- \(2x^2 + 2x - 12 = 2(x^2 + x - 6) = 2(x + 3)(x - 2)\)
- \(2x^2 - 11x + 15 = (2x - 5)(x - 3)\)
- \(3x^2 - 34x - 24 = (3x + 2)(x - 12)\)
- \(5x^2 - 27x + 10 = (5x - 2)(x - 5)\)
Section D:更複雜首項係數的二次式因式分解與挑戰題
- \(4x^2 + 12x + 8 = 4(x^2 + 3x + 2) = 4(x + 1)(x + 2)\)
- \(6x^2 + 23x + 20 = (2x + 5)(3x + 4)\)
- \(6x^2 + 24x + 18 = 6(x^2 + 4x + 3) = 6(x + 1)(x + 3)\)
- \(4x^2 + 31x + 21 = (4x + 3)(x + 7)\)
- \(4x^2 + 22x + 18 = 2(2x^2 + 11x + 9) = 2(2x + 9)(x + 1)\)
- \(8x^2 - 22x + 15 = (2x - 3)(4x - 5)\)
- \(8x^2 + 36x + 16 = 4(2x^2 + 9x + 4) = 4(2x + 1)(x + 4)\)
- \(6x^2 - 5x - 4 = (2x + 1)(3x - 4)\)
- \(6x^2 - 16x + 10\)(原圖為 \(6x^2 - 16x + 15\),此式在實數範圍內無法分解。若為 \(6x^2 - 16x + 10\),則為 \(2(3x - 5)(x - 1)\))
- \(8x^2 + 16x - 24 = 8(x^2 + 2x - 3) = 8(x + 3)(x - 1)\)
- \(7x^2 + 52x - 32 = (7x - 4)(x + 8)\)
- \(6x^2 - 55x + 56 = (6x - 7)(x - 8)\)
- \(9x^2 + 36x + 35 = (3x + 5)(3x + 7)\)
- \(12x^2 - 42x + 30 = 6(2x^2 - 7x + 5) = 6(2x - 5)(x - 1)\)
- \(48x^2 + 72x + 24 = 24(2x^2 + 3x + 1) = 24(2x + 1)(x + 1)\)
- \(18x^2 + 51x + 8\)(原圖為 \(18x^2 + 51x + 8\),此式無法分解。若為 \(18x^2 + 51x + 8\) 則保持原樣;若為 \(18x^2 + 51x + 30 = 3(6x^2 + 17x + 10) = 3(2x + 5)(3x + 2)\))
- \(20x^2 + 27x + 9 = (4x + 3)(5x + 3)\)
- \(30x^2 - 32x + 8 = 2(15x^2 - 16x + 4) = 2(3x - 2)(5x - 2)\)
- \(36x^2 + 42x - 8 = 2(18x^2 + 21x - 4) = 2(6x - 1)(3x + 4)\)
- \(24x^2 - 50x - 14 = 2(12x^2 - 25x - 7) = 2(4x + 1)(3x - 7)\)
- \(-2x^2 + x + 21 = -(2x^2 - x - 21) = -(2x - 7)(x + 3)\)
</reasoning>
<answer>
Section A
- \((x + 10)(x - 3)\)
- \((x + 4)(x + 5)\)
- \((x + 9)(x - 1)\)
- \((x - 8)(x - 10)\)
- \((x - 4)(x - 7)\)
- \((x + 12)(x - 6)\)
- \((x - 11)(x + 2)\)
- \((x - 4)(x + 3)\)
- \((x + 12)(x - 9)\)
- \((x - 8)(x - 9)\)
- \((x - 7)(x + 6)\)
- \((x - 7)(x - 8)\)
Section B
- \((2x + 1)(x + 1)\)
- \((2x + 1)(x + 2)\)
- \((2x + 1)(x + 3)\)
- \((2x + 5)(x + 1)\)
- \((2x + 7)(x + 1)\)
- \((2x + 3)(x + 1)\)
- \(2(x + 1)(x + 3)\)
- \((2x + 5)(x + 2)\)
- \(2(x + 1)(x + 7)\)
- \(2(x^2 + 5x + 12)\)
- \(2(x + 3)^2\)
- \(2(x + 2)(x + 5)\)
- \(2(x + 2)(x + 9)\)
- \(2(x + 2)(x + 12)\)
- \(2(x + 4)(x + 9)\)
Section C
- \((2x - 1)(x + 1)\)
- \((2x + 3)(x - 1)\)
- \((2x - 1)(x + 5)\)
- \((2x + 1)(x - 2)\)
- \((2x + 3)(x - 8)\)
- \((3x + 1)(x - 5)\)
- \((3x - 11)(x + 1)\)
- \(2(x - 1)(x - 6)\)
- \(3(x - 3)(x - 4)\)
- \((5x + 1)(x - 8)\)
- \((3x + 7)(x - 3)\)
- \(2(x + 3)(x - 2)\)
- \((2x - 5)(x - 3)\)
- \((3x + 2)(x - 12)\)
- \((5x - 2)(x - 5)\)
Section D
- \(4(x + 1)(x + 2)\)
- \((2x + 5)(3x + 4)\)
- \(6(x + 1)(x + 3)\)
- \((4x + 3)(x + 7)\)
- \(2(2x + 9)(x + 1)\)
- \((2x - 3)(4x - 5)\)
- \(4(2x + 1)(x + 4)\)
- \((2x + 1)(3x - 4)\)
- \(6x^2 - 16x + 15\) (無法在有理數範圍內分解)
- \(8(x + 3)(x - 1)\)
- \((7x - 4)(x + 8)\)
- \((6x - 7)(x - 8)\)
- \((3x + 5)(3x + 7)\)
- \(6(2x - 5)(x - 1)\)
- \(24(2x + 1)(x + 1)\)
- \(18x^2 + 51x + 8\) (無法在有理數範圍內分解)
- \((4x + 3)(5x + 3)\)
- \(2(3x - 2)(5x - 2)\)
- \(2(6x - 1)(3x + 4)\)
- \(2(4x + 1)(3x - 7)\)
- \(-(2x - 7)(x + 3)\)
</answer>
<post_analysis>
{
"subject": "Mathematics",
"question_type": "Multi-part",
"knowledge_point": [
"Mathematics",
"Algebra",
"Quadratic Factoring"
]
}
</post_analysis>