Question

experiment 1: write the balanced chemical reaction that occurs in this experiment for the removal of the waters of hydration from the copper(ii) sulfate hydrate.

balanced chemical equation:

Explanation:

Identify the reactant formula

We start with copper(II) sulfate hydrate. Using Chemical Nomenclature and Hydrate Formulas, copper(II) sulfate pentahydrate is the standard laboratory hydrate form of copper(II) sulfate, which has the chemical formula \(\text{CuSO}_4 \cdot 5\text{H}_2\text{O}\).

Identify the products

The reaction removes the waters of hydration. This thermal dehydration yields anhydrous copper(II) sulfate, \(\text{CuSO}_4\), and water vapor, \(\text{H}_2\text{O}\).

Write and balance the equation

Using Chemical Equation Balancing, we write the unbalanced reaction:

$$\text{CuSO}_4 \cdot 5\text{H}_2\text{O}(s) ightarrow \text{CuSO}_4(s) + \text{H}_2\text{O}(g)$$

To balance the oxygen and hydrogen atoms, we place a coefficient of 5 in front of the water molecule:

$$\text{CuSO}_4 \cdot 5\text{H}_2\text{O}(s) ightarrow \text{CuSO}_4(s) + 5\text{H}_2\text{O}(g)$$

Answer:

Experiment 1: Write the balanced chemical reaction that occurs in this experiment for the removal of the waters of hydration from the copper(II) sulfate hydrate.

balanced chemical equation: <blank>\(\text{CuSO}_4 \cdot 5\text{H}_2\text{O}(s)
ightarrow \text{CuSO}_4(s) + 5\text{H}_2\text{O}(g)\)</blank>