Question

example 4 use real numbers
on wednesday, there is an 83\\(\frac{1}{3}\\)% chance of rain. on thursday, there
is a \\(\frac{9}{10}\\) chance of rain. on friday, there is a 6 out of 7 chance that it
will rain.
on which day is there the greatest chance of rain?
step 1 write each number in decimal notation. round to the nearest
hundredth.
83\\(\frac{1}{3}\\)% = \\(\frac{9}{10}\\) = 6 out of 7 ≈
step 2 order the decimals.
since 0.9 > 0.86 > 0.83, then \\(\frac{9}{10}\\) \\(\frac{6}{7}\\) 83\\(\frac{1}{3}\\)%.
so, there is the greatest chance it will rain on thursday.
check
the table shows the on - base statistics for three players at a recent
baseball tournament. which player had the greatest on - base statisti

Explanation:

Step1: Convert each on - base statistic to decimal

• For Player 1: \(15\div21\approx0.71\)
• For Player 2: \(14\div19\approx0.74\)
• For Player 3: \(72.5\% = 0.725\)

Step2: Order the decimals

Since \(0.74>0.725 > 0.71\), then \(\frac{14}{19}>72.5\%>15\) out of \(21\)

Answer:

Player 2 had the greatest on - base statistic.