Question

the ericsson method is one of several methods claimed to increase the likelihood of a baby girl. in a clinical trial, results could be analyzed with a formal hypothesis test with the alternative hypothesis of ( p>0.5 ), which corresponds to the claim that the method increases the likelihood of having a girl, so that the proportion of girls is greater than 0.5. if you have an interest in establishing the success of the method, which of the following p-values would you prefer 0.999, 0.5, 0.95, 0.05, 0.01, 0.001? why? the p - value of is preferred because it corresponds to the sample evidence that most strongly supports the alternative hy method is effective. 0.5 0.95 0.001 0.01 0.05 0.999

Explanation:

In hypothesis testing, a smaller \( P - value \) provides stronger evidence against the null hypothesis (\( H_0:p = 0.5 \)) and in favor of the alternative hypothesis (\( H_1:p>0.5 \)). Among the given \( P - values\) (\(0.999\), \(0.5\), \(0.95\), \(0.05\), \(0.01\), \(0.001\)), the \( P - value\) of \(0.001\) is the smallest. A small \( P - value\) (such as \(0.001\)) means that if the null hypothesis were true, the probability of getting the observed sample data (or more extreme data in the direction of the alternative hypothesis) is very low. So, it gives strong support to the claim that the method is effective (the alternative hypothesis).

Answer:

The \( P - value\) of \(0.001\) is preferred because it corresponds to the sample evidence that most strongly supports the alternative hypothesis (the method is effective).