Question

enter the symbol of a sodium ion, $\ce{na^{+}}$, followed by the formula of a sulfate ion, $\ce{so4}$. express your answers as ions separated by a comma.

enter the expression $\ce{^{14}_{7}n + \alpha}$, where $\alpha$ is the lowercase greek letter alpha. express your answer as a chemical expression.

Explanation:

Part B

Step 1: Identify the sodium ion symbol

The sodium ion is given as \( \ce{Na+} \).

Step 2: Identify the sulfate ion formula

The sulfate ion has the formula \( \ce{SO4^{2 - }} \).

Part C

Step 1: Recall the symbol for the alpha particle

An alpha particle (\( \alpha \)) is equivalent to a helium - 4 nucleus, which is represented as \( \ce{He^{2+}} \) or \( \ce{^4_2He} \). In the context of nuclear reactions, when writing \( ^{14}_7\ce{N}+\alpha \), we use the nuclear notation for the alpha particle.

Answer:

• Part B: \( \ce{Na+},\ce{SO4^{2 - }} \)
• Part C: \( ^{14}_7\ce{N}+^{4}_2\ce{He} \)