Question

elements for this property.

1. analyze the tuva data set.

select the correct statement(s) about electronegativity.
electronegativity from highest to lowest is osmium (os), chlorine (cl), oxygen (o), and fluorine (f).
it decreases as you move down a group.
it increases as you move across a period.
it decreases as you move across a period.
it increases as you move down a group.
electronegativity from highest to lowest is fluorine (f), oxygen (o), chlorine (cl) and osmium (os).

Explanation:

Electronegativity is a measure of an atom's ability to attract electrons in a chemical bond.

• Trend down a group: As you move down a group in the periodic table, the number of electron shells increases. This leads to a decrease in electronegativity because the outermost electrons are farther from the nucleus and are less strongly attracted.
• Trend across a period: As you move across a period from left to right, the nuclear charge increases while the number of electron shells remains the same. This results in an increase in electronegativity as the nucleus can attract electrons more strongly.
• Electronegativity values: Fluorine (F) is the most electronegative element (\(EN = 3.98\)), oxygen (O) has \(EN=3.44\), chlorine (Cl) has \(EN = 3.16\), and osmium (Os) has \(EN=2.2\). So the order from highest to lowest is \(F>O>Cl>Os\).

Answer:

• It decreases as you move down a group.
• It increases as you move across a period.
• Electronegativity from highest to lowest is fluorine (F), oxygen (O), chlorine (Cl) and osmium (Os).