Question

elements elements in order of decreasing electronegativity as,s,se si,s,p

Explanation:

Step1: Recall the trend of electronegativity

Electronegativity increases across a period (from left to right) and decreases down a group in the periodic table.

Step2: Analyze the first set of elements (As, S, Se)

• S and Se are in the same group (Group 16). Since electronegativity decreases down a group, \(S>Se\).
• As is in Group 15. In the third - fourth period, for elements in adjacent groups, elements in the higher - numbered group (Group 16) have higher electronegativity than those in the lower - numbered group (Group 15) when in the same period range. So \(S>Se>As\).

Step3: Analyze the second set of elements (Si, S, P)

• Si, P, S are in the same period (Period 3). Since electronegativity increases across a period (from left to right), \(S > P>Si\).

Answer:

For \(As,S,Se\): \(S>Se>As\)
For \(Si,S,P\): \(S > P>Si\)