Question

the electron configuration for iodine is below, what is the highest occupied energy level of the electrons xe 6s² 4f¹⁴ 5d¹⁰ 6p² 5 2 6 4

Explanation:

In electron configuration, the number before the orbital (like \(s\), \(p\), \(d\), \(f\)) represents the energy level. For iodine's electron configuration \([Xe]6s^{2}4f^{14}5d^{10}6p^{2}\), we look at the highest number among the leading numbers of the orbitals. The orbitals here are \(6s\), \(4f\), \(5d\), \(6p\). The highest number is \(6\).

Answer:

6