Question

the distribution of the number of times students eat out per week is as follows.

find the probability of eating out 3 times.

\\(p(3) = \quad\\%\\)

round your answer to the nearest whole percent.

Explanation:

Sum of probabilities

Using the Probability Distributions knowledge point

$$ \sum P(x) = 100\% $$

Set up equation

Using the Probability Distributions and Complementary Probability knowledge points

$$ P(0) + P(1) + P(2) + P(3) = 100\% $$

Substitute known values

Using the Probability Distributions knowledge point

$$ 17\% + 40\% + 29\% + P(3) = 100\% $$

Solve for P(3)

Using the Probability Distributions knowledge point

$$
LATEXBLOCK0
$$

Answer:

Find the probability of eating out 3 times.

\(P(3) =\) <blank>14</blank>%