Question

determine whether this table represents a probability distribution.

$x$	$p(x)$
1	0.25
2	0.2
3	0.5

no, it is not a probability distribution
yes, it is a probability distribution

Explanation:

Step1: Check non - negativity

All $P(x)$ values $0.1, 0.25, 0.2, 0.5$ are non - negative.

Step2: Check sum of probabilities

Calculate $\sum_{x}P(x)=0.1 + 0.25+0.2 + 0.5=1.05$. Since $\sum_{x}P(x)
eq1$, it does not meet the criteria for a probability distribution.

Answer:

No, it is not a probability distribution