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determine the range and standard deviation of the set of data, round to…

Question

determine the range and standard deviation of the set of data, round to the nearest hundredth when applicable.

  1. 10, 10, 14, 16, 8, 8
  2. 3, 5, 7, 9, 11, 13, 15
  3. 1, 3, 71, 8, 92, 63
  4. 5, 10, 20, 200, 300, 400
  5. 0, 3, 5, 9, 9, 10, 11, 13

Explanation:

Step1: Calculate the range

The range is the difference between the maximum and minimum values in the data set.
For the data set \(10,10,14,16,8,8\):
Maximum value \(M = 16\), minimum value \(m=8\)
Range \(R = M - m=16 - 8=8\)

Step2: Calculate the mean

The mean \(\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}\), where \(n\) is the number of data points and \(x_{i}\) are the data values.
\(n = 6\), \(\sum_{i=1}^{6}x_{i}=10 + 10+14 + 16+8 + 8=66\)
\(\bar{x}=\frac{66}{6}=11\)

Step3: Calculate the variance

The variance \(s^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}\)
\((10 - 11)^{2}=1\), \((10 - 11)^{2}=1\), \((14 - 11)^{2}=9\), \((16 - 11)^{2}=25\), \((8 - 11)^{2}=9\), \((8 - 11)^{2}=9\)
\(\sum_{i = 1}^{6}(x_{i}-\bar{x})^{2}=1+1 + 9+25+9+9=54\)
\(s^{2}=\frac{54}{6 - 1}=\frac{54}{5}=10.8\)

Step4: Calculate the standard deviation

The standard deviation \(s=\sqrt{s^{2}}\)
\(s=\sqrt{10.8}\approx3.29\)

Answer:

Range: \(8\), Standard deviation: \(3.29\)

(Note: The above steps are for the first data - set \(10,10,14,16,8,8\). For other data - sets, the process is similar:

  1. For data set \(3,5,7,9,11,13,15\):
  • Range: \(15 - 3=12\)
  • Mean \(\bar{x}=\frac{3 + 5+7+9+11+13+15}{7}=\frac{63}{7}=9\)
  • \(\sum_{i = 1}^{7}(x_{i}-\bar{x})^{2}=(3 - 9)^{2}+(5 - 9)^{2}+(7 - 9)^{2}+(9 - 9)^{2}+(11 - 9)^{2}+(13 - 9)^{2}+(15 - 9)^{2}=36+16 + 4+0+4+16+36 = 112\)
  • Variance \(s^{2}=\frac{112}{7 - 1}=\frac{112}{6}\approx18.67\)
  • Standard deviation \(s=\sqrt{\frac{112}{6}}\approx4.32\)
  1. For data set \(1,3,71,8,92,63\):
  • Range: \(92 - 1=91\)
  • Mean \(\bar{x}=\frac{1+3 + 71+8+92+63}{6}=\frac{238}{6}\approx39.67\)
  • \(\sum_{i = 1}^{6}(x_{i}-\bar{x})^{2}=(1 - 39.67)^{2}+(3 - 39.67)^{2}+(71 - 39.67)^{2}+(8 - 39.67)^{2}+(92 - 39.67)^{2}+(63 - 39.67)^{2}\approx(- 38.67)^{2}+(-36.67)^{2}+(31.33)^{2}+(-31.67)^{2}+(52.33)^{2}+(23.33)^{2}=1495.37+1344.79+981.57+1002.99+2738.43+544.29 = 8107.44\)
  • Variance \(s^{2}=\frac{8107.44}{6 - 1}=\frac{8107.44}{5}=1621.49\)
  • Standard deviation \(s=\sqrt{1621.49}\approx40.27\)
  1. For data set \(5,10,20,200,300,400\):
  • Range: \(400 - 5=395\)
  • Mean \(\bar{x}=\frac{5+10+20+200+300+400}{6}=\frac{935}{6}\approx155.83\)
  • \(\sum_{i = 1}^{6}(x_{i}-\bar{x})^{2}=(5 - 155.83)^{2}+(10 - 155.83)^{2}+(20 - 155.83)^{2}+(200 - 155.83)^{2}+(300 - 155.83)^{2}+(400 - 155.83)^{2}\approx(-150.83)^{2}+(-145.83)^{2}+(-135.83)^{2}+(44.17)^{2}+(144.17)^{2}+(244.17)^{2}=22749.69+21268.39+18450.79+1950.99+20784.99+59619.09 = 144823.94\)
  • Variance \(s^{2}=\frac{144823.94}{6 - 1}=\frac{144823.94}{5}=28964.79\)
  • Standard deviation \(s=\sqrt{28964.79}\approx170.20\)
  1. For data set \(0,3,5,9,9,10,11,13\):
  • Range: \(13 - 0=13\)
  • Mean \(\bar{x}=\frac{0+3+5+9+9+10+11+13}{8}=\frac{60}{8}=7.5\)
  • \(\sum_{i = 1}^{8}(x_{i}-\bar{x})^{2}=(0 - 7.5)^{2}+(3 - 7.5)^{2}+(5 - 7.5)^{2}+(9 - 7.5)^{2}+(9 - 7.5)^{2}+(10 - 7.5)^{2}+(11 - 7.5)^{2}+(13 - 7.5)^{2}=56.25+20.25+6.25+2.25+2.25+6.25+12.25+30.25 = 136\)
  • Variance \(s^{2}=\frac{136}{8 - 1}=\frac{136}{7}\approx19.43\)
  • Standard deviation \(s=\sqrt{\frac{136}{7}}\approx4.41\))