Question

determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, x, for the sample size provided
lower bound ( = 0.322 ), upper bound ( = 0.728 ), ( n = 1200 )
the point estimate of the population proportion is
(round to the nearest thousandth as needed.)

Explanation:

Step1: Recall the formula for point estimate

The point estimate $\hat{p}$ of the population proportion is given by the formula $\hat{p}=\frac{\text{Lower bound}+\text{Upper bound}}{2}$.

Step2: Substitute the given values

Substitute Lower bound = $0.322$ and Upper bound = $0.728$ into the formula:
$$\hat{p}=\frac{0.322 + 0.728}{2}$$

Step3: Calculate the value

First, add the values in the numerator: $0.322+0.728 = 1.05$. Then divide by 2: $\frac{1.05}{2}=0.525$.

Answer:

$0.525$