Question

determine the electron geometry of h₂s. pentahedral trigonal planar hexahedral linear tetrahedral

Explanation:

To determine the electron geometry of \(H_2S\), we use the VSEPR (Valence - Shell Electron - Pair Repulsion) theory.

• First, find the number of electron - pairs around the central atom (\(S\)).
• The central atom \(S\) has 6 valence electrons. Each \(H\) atom contributes 1 electron. So the total number of valence electrons in \(H_2S\) is \(6+(1\times2)=8\).
• The number of bonding pairs: Since each \(H - S\) bond is a single bond, there are 2 bonding pairs.
• The number of non - bonding (lone) pairs: Using the formula \(n=\frac{\text{Valence electrons}-\text{Number of bonding electrons}}{2}\), we have \(n=\frac{8 - 4}{2}=2\) lone pairs.
• The total number of electron pairs (bonding + non - bonding) around \(S\) is \(2 + 2=4\).
• According to VSEPR theory, when the number of electron pairs around a central atom is 4, the electron geometry is tetrahedral. The electron - pair geometry is determined by the total number of electron pairs (bonding and non - bonding) around the central atom.

Answer:

tetrahedral