Question

decide whether these proposed lewis structures are reasonable.
proposed lewis structure is the proposed lewis structure reasonable?
h — h — o
yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *
c = o
yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *
n = n
yes.
no, it has the wrong number of valence electrons.
the correct number is:
no, it has the right number of valence electrons but doesnt satisfy the octet rule.
the symbols of the problem atoms are: *

• if two - or more atoms of the same element dont satisfy the octet rule, just enter the chemical symbol as many times as necessary. for example, if two oxygen atoms dont satisfy the octet rule, enter \o,o\.

Explanation:

Step1: Calculate valence - electrons for H₂O

Hydrogen (H) has 1 valence electron and oxygen (O) has 6 valence electrons. In H₂O, the total number of valence electrons is \(2\times1 + 6=8\). The given structure \(H - H - O\) is incorrect as hydrogen atoms should be bonded to oxygen, not to each other. The correct Lewis structure has two \(H - O\) single bonds. The number of valence electrons in the correct structure is 8. The given structure has the wrong number of bonding patterns and thus the wrong number of valence - electrons representation.

Step2: Calculate valence - electrons for CO

Carbon (C) has 4 valence electrons and oxygen (O) has 6 valence electrons. So, the total number of valence electrons for CO is \(4 + 6=10\). The given Lewis structure \(C = O\) with each atom having 3 lone - pairs is correct in terms of the number of valence electrons (2 bonding electrons and 8 non - bonding electrons). Both C and O satisfy the octet rule.

Step3: Calculate valence - electrons for N₂

Nitrogen (N) has 5 valence electrons. In N₂, the total number of valence electrons is \(2\times5 = 10\). The given Lewis structure \(N = N\) with each N having 3 lone - pairs has the wrong number of valence electrons. The correct Lewis structure of N₂ is \(N\equiv N\) with each N having 1 lone - pair, and the correct number of valence electrons is 10.

Answer:

1. No, it has the wrong number of valence electrons. The correct number is: 8
2. Yes.
3. No, it has the wrong number of valence electrons. The correct number is: 10