Question

a data set includes 109 body temperatures of healthy adult humans having a mean of 98.2°f and a standard deviation of 0.62°f. construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. what does the sample suggest about the use of 98.6°f as the mean body temperature? click here to view a t distribution table. click here to view page 1 of the standard normal distribution table. click here to view page 2 of the standard normal distribution table. what is the confidence interval estimate of the population mean μ? 98.044°f < μ < 98.356°f (round to three decimal places as needed.) what does this suggest about the use of 98.6°f as the mean body temperature? a. this suggests that the mean body temperature could very possibly be 98.6°f. b. this suggests that the mean body temperature is higher than 98.6°f. c. this suggests that the mean body temperature is lower than 98.6°f.

Explanation:

Step1: Analyze the confidence interval

The confidence interval is \(98.044^{\circ}F<\mu < 98.356^{\circ}F\).

Step2: Compare with \(98.6^{\circ}F\)

Since \(98.6^{\circ}F\) is not within the interval \(98.044^{\circ}F - 98.356^{\circ}F\), and all values in the interval are less than \(98.6^{\circ}F\).

Answer:

C. This suggests that the mean body temperature is lower than \(98.6^{\circ}F\)