Question

cross charges to form an ionic compound. write the correct chemical formula.

1. lithium + chlorine

li+1
cl-1

1. barium + sulfur

ba+2
s-2

1. sodium + oxygen

na+1
o-2

1. aluminum + nitrogen

al+3
n-3

1. sodium + sulfur

na+1
s-2

1. barium + oxygen

ba+2
o-2

Explanation:

Step1: Determine charges

For lithium chloride: \(Li\) has a charge of \(+1\) (\(Li^{+}\)) and \(Cl\) has a charge of \(-1\) (\(Cl^{-}\)).

Step2: Cross - multiply charges

Using the criss - cross method, the charges are \(1\) and \(1\). So the formula is \(LiCl\).

For barium sulfide: \(Ba\) has a charge of \(+2\) (\(Ba^{2+}\)) and \(S\) has a charge of \(-2\) (\(S^{2 -}\)).

Step3: Cross - multiply charges

Using the criss - cross method, the charges are \(2\) and \(2\). Dividing by the greatest common divisor (\(2\)), the formula is \(BaS\).

For sodium oxide: \(Na\) has a charge of \(+1\) (\(Na^{+}\)) and \(O\) has a charge of \(-2\) (\(O^{2 -}\)).

Step4: Cross - multiply charges

Using the criss - cross method, the formula is \(Na_{2}O\).

For aluminum nitride: \(Al\) has a charge of \(+3\) (\(Al^{3+}\)) and \(N\) has a charge of \(-3\) (\(N^{3 -}\)).

Step5: Cross - multiply charges

Using the criss - cross method, the charges are \(3\) and \(3\). Dividing by the greatest common divisor (\(3\)), the formula is \(AlN\).

For sodium sulfide: \(Na\) has a charge of \(+1\) (\(Na^{+}\)) and \(S\) has a charge of \(-2\) (\(S^{2 -}\)).

Step6: Cross - multiply charges

Using the criss - cross method, the formula is \(Na_{2}S\).

For barium oxide: \(Ba\) has a charge of \(+2\) (\(Ba^{2+}\)) and \(O\) has a charge of \(-2\) (\(O^{2 -}\)).

Step7: Cross - multiply charges

Using the criss - cross method, the charges are \(2\) and \(2\). Dividing by the greatest common divisor (\(2\)), the formula is \(BaO\).

Answer:

1. \(LiCl\)
2. \(BaS\)
3. \(Na_{2}O\)
4. \(AlN\)
5. \(Na_{2}S\)
6. \(BaO\)