QUESTION IMAGE
Question
a countrys tax collection agency reported that 92% of individual tax returns were filed electronically in 2017. a random sample of 210 tax returns from 2018 was selected. from this sample, 181 were filed electronically. complete parts a through c.
a. construct a 90% confidence interval to estimate the actual proportion of taxpayers who filed electronically in 2018.
the confidence interval has a lower limit of \\( \square \\) and an upper limit of \\( \square \\).
(round to three decimal places as needed.)
Step1: Calculate sample proportion
The sample proportion $\hat{p}=\frac{x}{n}$, where $x = 181$ and $n=210$. So, $\hat{p}=\frac{181}{210}\approx0.862$.
Step2: Find critical value
For a 90% confidence interval, the significance level $\alpha=1 - 0.90=0.10$, and $\alpha/2=0.05$. The critical value $z_{\alpha/2}=z_{0.05}\approx1.645$ (from standard normal distribution table).
Step3: Calculate margin of error
The margin of error $E = z_{\alpha/2}\sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}$. Substitute $\hat{p}=0.862$, $n = 210$, and $z_{\alpha/2}=1.645$.
First, calculate $\hat{p}(1-\hat{p})=0.862\times(1 - 0.862)=0.862\times0.138 = 0.119$.
Then, $\sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}=\sqrt{\frac{0.119}{210}}\approx\sqrt{0.000567}\approx0.024$.
$E=1.645\times0.024\approx0.040$.
Step4: Calculate confidence interval
The lower limit $= \hat{p}-E=0.862 - 0.040=0.822$.
The upper limit $=\hat{p}+E=0.862+0.040 = 0.902$.
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The confidence interval has a lower limit of $0.822$ and an upper limit of $0.902$.