Question

constructing a two-way table using driving data
distribution of mileage efficiencies across different weight classes
based on the table, what is the missing value for medium-weight cars in the high-mileage category?
(table with columns: weight, high mileage, medium mileage, low mileage, total; rows: light (2,1,0,3), medium (?,2,1,3), heavy (0,?,2,2), total (2,3,3,8))
options: 2, 1, 3, 0

Explanation:

Step1: Recall total formula

For a row in a two - way table, the sum of the values in the "High Mileage", "Medium Mileage", and "Low Mileage" columns should equal the value in the "Total" column. For the "Medium" weight class row, we have the formula: High Mileage + Medium Mileage + Low Mileage = Total.

Step2: Substitute known values

We know that for the "Medium" weight class, Medium Mileage = 2, Low Mileage = 1, and Total = 3. Let the missing value (High Mileage for medium - weight cars) be \(x\). Then we have the equation \(x + 2+1=3\).

Step3: Solve the equation

Simplify the left - hand side of the equation: \(x + 3=3\). Subtract 3 from both sides of the equation: \(x=3 - 3=0\).

Answer:

0