Question

1. a compound has the empirical formula of ch₂o.

what is the molecular formula when the molecular weight is 180.0 grams?
enter the correct answer in the box.

Explanation:

Step1: Calculate the empirical formula weight

The empirical formula is \(CH_2O\).
The atomic weights: \(C = 12.01\space g/mol\), \(H= 1.008\space g/mol\), \(O = 16.00\space g/mol\).
Empirical formula weight \(=12.01+(2\times1.008)+16.00=30.026\space g/mol\)

Step2: Find the ratio \(n\)

\(n=\frac{\text{Molecular weight}}{\text{Empirical formula weight}}=\frac{180.0}{30.026}\approx6\)

Step3: Determine the molecular formula

Multiply each sub - script in the empirical formula by \(n\).
For \(CH_2O\), the molecular formula is \(C_{6}H_{12}O_{6}\)

Answer:

\(C_{6}H_{12}O_{6}\)