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in the compound crp, the charge of the chromium ion is +2. false true t…

Question

in the compound crp, the charge of the chromium ion is +2.
false
true
the correct chemical formula for iron(iii) chloride is fecl₂.
true
false
the compound is v(no₃)₃. if the first part of the name is vanadium, what roman numeral must come right after it?
your answer
which compound name correctly uses a roman numeral to show the charge of the metal?
copper bromide
zinc (ii) nitrate
silver (i) oxide
manganese (iii) sulfate

Explanation:

First Question (In the compound CrP, the charge of the chromium ion is +2.)
Brief Explanations

In CrP, phosphorus (P) typically has a -3 charge in ionic compounds. For the compound to be neutral, let the charge of Cr be \( x \). So \( x + (-3) = 0 \), which gives \( x = +3 \). So the statement is false.

Brief Explanations

Iron(III) means the iron ion has a +3 charge (\( Fe^{3+} \)), and chloride is \( Cl^- \). To balance charges, we need 3 \( Cl^- \) for 1 \( Fe^{3+} \), so the formula should be \( FeCl_3 \), not \( FeCl_2 \). So the statement is false.

Step 1: Determine the charge of nitrate ion

Nitrate (\( NO_3^- \)) has a charge of -1.

Step 2: Calculate the charge of Vanadium ion

In \( V(NO_3)_4 \), let the charge of V be \( x \). There are 4 nitrate ions, so the total negative charge is \( 4\times(-1)= - 4 \). For the compound to be neutral, \( x+(-4)=0 \), so \( x = +4 \).

Answer:

False

Second Question (The correct chemical formula for Iron(III) chloride is \( FeCl_2 \).)