Question

complete the following table: cation formula anion formula compound formula ag+ ca2+ cr2+ s2- so32- po43-

Explanation:

Step1: Combine cations and anions

To form a neutral - charge compound, the total positive charge must equal the total negative charge.

Step2: For $Ag^+$ and $S^{2 -}$

The compound formula is $Ag_2S$ because two $Ag^+$ (each with a + 1 charge) are needed to balance the - 2 charge of $S^{2 -}$.

Step3: For $Ag^+$ and $SO_3^{2 -}$

The compound formula is $Ag_2SO_3$ as two $Ag^+$ are required to neutralize the - 2 charge of $SO_3^{2 -}$.

Step4: For $Ag^+$ and $PO_4^{3 -}$

The compound formula is $Ag_3PO_4$ since three $Ag^+$ (each with + 1 charge) are needed to balance the - 3 charge of $PO_4^{3 -}$.

Step5: For $Ca^{2 +}$ and $S^{2 -}$

The compound formula is $CaS$ because the + 2 charge of $Ca^{2 +}$ balances the - 2 charge of $S^{2 -}$.

Step6: For $Ca^{2 +}$ and $SO_3^{2 -}$

The compound formula is $CaSO_3$ as the + 2 charge of $Ca^{2 +}$ neutralizes the - 2 charge of $SO_3^{2 -}$.

Step7: For $Ca^{2 +}$ and $PO_4^{3 -}$

The compound formula is $Ca_3(PO_4)_2$. Here, three $Ca^{2 +}$ (total + 6 charge) are needed to balance two $PO_4^{3 -}$ (total - 6 charge).

Step8: For $Cr^{2 +}$ and $S^{2 -}$

The compound formula is $CrS$ as the + 2 charge of $Cr^{2 +}$ balances the - 2 charge of $S^{2 -}$.

Step9: For $Cr^{2 +}$ and $SO_3^{2 -}$

The compound formula is $CrSO_3$ since the + 2 charge of $Cr^{2 +}$ neutralizes the - 2 charge of $SO_3^{2 -}$.

Step10: For $Cr^{2 +}$ and $PO_4^{3 -}$

The compound formula is $Cr_3(PO_4)_2$. Three $Cr^{2 +}$ (total + 6 charge) are required to balance two $PO_4^{3 -}$ (total - 6 charge).

Answer:

Cation	Anion	Compound Formula
$Ag^+$	$SO_3^{2 -}$	$Ag_2SO_3$
$Ag^+$	$PO_4^{3 -}$	$Ag_3PO_4$
$Ca^{2 +}$	$S^{2 -}$	$CaS$
$Ca^{2 +}$	$SO_3^{2 -}$	$CaSO_3$
$Ca^{2 +}$	$PO_4^{3 -}$	$Ca_3(PO_4)_2$
$Cr^{2 +}$	$S^{2 -}$	$CrS$
$Cr^{2 +}$	$SO_3^{2 -}$	$CrSO_3$
$Cr^{2 +}$	$PO_4^{3 -}$	$Cr_3(PO_4)_2$